From 702f09d0de0b2fee9a7aeda22658745f76df291b Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E5=88=98=E5=8D=8E=E6=B8=85?= <18691022700@163.com>
Date: Mon, 22 Dec 2025 17:43:32 +0800
Subject: [PATCH] =?UTF-8?q?=E5=AE=8C=E5=96=84=E6=8A=A2=E7=BA=A2=E5=8C=85?=
 =?UTF-8?q?=E9=80=BB=E8=BE=91?=
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---
 application/common/library/RedpacketLua.php | 30 ++++++++++++---------
 1 file changed, 18 insertions(+), 12 deletions(-)

diff --git a/application/common/library/RedpacketLua.php b/application/common/library/RedpacketLua.php
index e5359ae6..952f24b2 100644
--- a/application/common/library/RedpacketLua.php
+++ b/application/common/library/RedpacketLua.php
@@ -69,29 +69,35 @@ if leftCount <= 0 or leftAmount <= 0 then
     return {0, "红包已抢完", 0}
 end
 
--- 计算红包金额
+-- 计算红包金额（核心修改：适配整数金币，避免0）
 local amount = 0
 local isFinished = 0
 
 if leftCount == 1 then
-    -- 最后一个红包，获得剩余所有金额
+    -- 最后一个红包，获得剩余所有金额（确保至少1）
     amount = leftAmount
     isFinished = 1
 else
-    -- 随机算法：二倍均值法，保证公平性
-    local maxAmount = leftAmount / leftCount * 2
-    amount = math.random(1, math.floor(maxAmount))
-    -- 确保金额不会超过剩余金额
-    if amount > leftAmount then
-        amount = leftAmount
-    end
-    -- 检查是否是最后一个（由于浮点数计算可能有误差）
-    if leftCount == 1 or (leftAmount - amount) < 0.01 then
+    -- 随机算法：二倍均值法（适配整数，保证最低1）
+    -- 1. 计算二倍均值（整数处理，向下取整）
+    local avg = leftAmount / leftCount
+    local maxAmount = math.floor(avg * 2)
+    -- 2. 确保最大金额至少为1，且不超过剩余金额-（剩余个数-1）（避免后续红包无金额可分）
+    --    剩余金额-（剩余个数-1）：保证剩下的每个红包至少能分1个金币
+    local safeMax = leftAmount - (leftCount - 1)
+    maxAmount = math.min(maxAmount, safeMax)
+    maxAmount = math.max(maxAmount, 1) -- 确保最小可随机值为1
+    
+    -- 3. 随机生成1到maxAmount之间的整数（避免0）
+    amount = math.random(1, maxAmount)
+    
+    -- 4. 检查是否抢完（整数判断，无需浮点数误差处理）
+    if leftCount - 1 == 1 or (leftAmount - amount) <= 0 then
         isFinished = 1
     end
 end
 
--- 更新红包数据
+-- 更新红包数据（整数处理，无小数）
 local newLeftAmount = leftAmount - amount
 local newLeftCount = leftCount - 1